The table gives a set of outcomes and their probabilities. Let A be the event "the outcome is prime". Let B be the event "the outcome is less than or equal to 2". Find P(AIB). Outcome Probability 1 0.2 2 0.3 3 0.2 4 4 0.3

Answer :

The conditional probability is given by:

[tex]P(A|B)=\frac{P(A\cap B)}{P(B)}[/tex]

Now, since the event A is "the outcome is prime" and the event B is "the outcome is less than or equal to 2" we have that:

[tex]P(B)=0.5[/tex]

and

[tex]P(A\cap B)=0.5[/tex]

Therefore:

[tex]P(A|B)=\frac{0.5}{0.5}=1[/tex]

Therefore the probability is 1.

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