This problem is a bit tricky for me to solve

SOLUTION
[tex]\begin{gathered} Given \\ \frac{x+6}{x-3}=\frac{4}{7} \end{gathered}[/tex]Cross multiply and simplify;
[tex]\begin{gathered} 7x+42=4x-12 \\ 7x-4x=-12-42 \\ 3x=-54 \\ x=\frac{-54}{3} \\ x=-18 \end{gathered}[/tex]The answer is -18.
OPTION D IS THE CORRECT ANSWER.