We will solve as follows:
*Area of the rectangle:
[tex]A_r=(4)(5)\Rightarrow A_r=20[/tex]*Area of the triangle:
[tex]A_t=\frac{(4)(3)}{2}\Rightarrow A_t=6[/tex]*Area of the figure:
[tex]A_f=A_r+A_t\Rightarrow A_f=20+6[/tex][tex]\Rightarrow A_f=26[/tex]