Answer :
Given that in one baseball season, Peter (p) hit twice the number of homeruns that Mark (m) hit. This can be interpreted algebraically as shown below:
[tex]p=2m[/tex]Also, given that together they hit 18 homeruns. This can be interpreted as shown below:
[tex]p+m=18[/tex]Substitute p = 2m in the total home runs to know the home runs each person hit as shown below:
[tex]\begin{gathered} p+m=18,p=2m \\ 2m+m=18 \\ 3m=18 \\ \text{divide through by 3} \end{gathered}[/tex][tex]\begin{gathered} \frac{3m}{3}=\frac{18}{3} \\ m=6 \end{gathered}[/tex]Substitute for m in p= 2m to p as shown below:
[tex]\begin{gathered} p=2m,m=6 \\ p=2\times6 \\ p=12 \end{gathered}[/tex]Hence, Peter hits 12 homeruns and Mark hits 6 homeruns