How to know which double angle COS formula to substitute in and why. Also if I should leave CSC^2 as it is or if I should change it to 1/SIN^2 to solve

How to know which double angle COS formula to substitute in and why. Also if I should leave CSC^2 as it is or if I should change it to 1/SIN^2 to solve class=

Answer :

It is given that:-

[tex]\begin{gathered} \csc ^2\beta\times\cos (2\beta) \\ =\frac{1}{\sin^2\beta}\times(\cos ^2\beta-\sin ^2\beta) \\ =\frac{\cos^2\beta}{\sin^2\beta}-\frac{\sin ^2\beta}{\sin ^2\beta} \\ =\cot ^2\beta-1 \end{gathered}[/tex]

So the correct answer is

[tex]\cot ^2\beta-1[/tex]

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