Answer :
Given:
The equation is,
[tex]x^2+7x+15[/tex]Explanation:
The solution of equation,
[tex]ax^2+bx+c=0[/tex]using quadratic formula is,
[tex]x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]Solve the equation using quadratic formula.
[tex]\begin{gathered} x=\frac{-7\pm\sqrt[]{(7)^2-4\cdot1\cdot15}}{2\cdot1} \\ =\frac{-7\pm\sqrt[]{49-60}}{2} \\ =\frac{-7\pm\sqrt[]{-11}}{2} \\ =\frac{-7\pm\sqrt[]{11}i}{2} \end{gathered}[/tex]So, solution of system of equation is,
[tex]x=\frac{-7\pm\sqrt[]{11}i}{2}[/tex]