Answer :

Solution

For this case we have the following sequence of numbers:

64,48 , 36, 27, ....

We can find the common difference on this way:

We can assume that we have a geometric sequence and we have this:

[tex]48=64(r)[/tex][tex]r=\frac{48}{64}=\frac{3}{4}[/tex]

Then we can write the general expression:

[tex]a_n=64(\frac{3}{4})^{n-1}[/tex]

For n = 1 we have a1 = 64

for n = 2 we have a2= 48

for n = 3 we have a3 = 36

for n = 4 we have a4= 27

For n = 5:

[tex]a_5=64(\frac{3}{4})^4=20.25[/tex]

For n =6:

[tex]a_6=64(\frac{3}{4})^5=15.1875[/tex]

then the next two terms are:

20.25 and 15.1875

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