Answer :
Recall that:
[tex]sin\theta=cos(90^{\circ}-\theta).[/tex]Therefore:
[tex]sin37^{\circ}=cos(90^{\circ}-37^{\circ}).[/tex]Simplifying the above result, we get:
[tex]sin37^{\circ}=cos53^{\circ}.[/tex]
Recall that:
[tex]sin\theta=cos(90^{\circ}-\theta).[/tex]Therefore:
[tex]sin37^{\circ}=cos(90^{\circ}-37^{\circ}).[/tex]Simplifying the above result, we get:
[tex]sin37^{\circ}=cos53^{\circ}.[/tex]