using the formula above, find the surface area of a cube whise sides are all two thirds inches

Given:
The sides of the cube is, s=2/3 inches.
The objective is to find the surface area of cube.
The surface area can be calculated as,
[tex]\begin{gathered} SA=6s^2 \\ =6(\frac{2}{3})^2 \\ =6(\frac{4}{9}) \\ =2.667in^2 \end{gathered}[/tex]Hence, the surface area of the cube is 2.667 square inches.