Hello!
First of all, let's write these numbers in the decimal form:
[tex]\sqrt{11}\cong3.32[/tex][tex]\frac{10}{9}\cong1.11[/tex]Knowing it, we have:
[tex]\begin{gathered} 3.32>1.11 \\ \text{ also} \\ \sqrt{11}>\frac{10}{9} \end{gathered}[/tex]Is greater than.