Answer :
ANSWER
The equation of the line that passes through (-1, 0) is y = 2x + 2
STEP-BY-STEP EXPLANATION
Given information
The given points on the graph are (-1, 0) and (0, 2)
From the given points, we can deduce the below data
x1 = -1
y1 = 0
x2 = 0
y2 = 2
The next step is to find the slope between the two points
[tex]\text{slope = }\frac{\text{ rise}}{\text{ run}}[/tex]Where
rise = y2 - y1
run = x2 - x1
[tex]\begin{gathered} \text{slope = }\frac{y2\text{ - y1}}{x2\text{ - x1}} \\ \text{slope = }\frac{\text{ 2 - 0}}{0\text{ - (-1)}} \\ \text{slope = }\frac{2}{0\text{ + 1}} \\ \text{slope = }\frac{2}{1} \\ \text{slope = 2} \end{gathered}[/tex]From the above equation, you will see that the slope between the two lines is 2
The next process is to find the equation of the line that passes through (-1, 0)
Recall that,
[tex]y\text{ = mx + b}[/tex]where,
m is the slope of the line
b is the intercept of the y-axis
For a given point, we will be using the formula below
[tex]\begin{gathered} (y\text{ - y1) = m(x - x1)} \\ m=2,x1\text{ = -1 and y1 = 0} \\ (y\text{ - 0) = 2(x - (-1)} \\ y\text{ - 0 = 2(x + 1)} \\ y\text{ = 2x + 2} \end{gathered}[/tex]