Given:
CB = 6
AC = 9
Since both triangles are similar triangles, to find DC, use the formula below:
[tex]\frac{DC}{CB}=\frac{CB}{AC}[/tex]Thus, we have:
[tex]\frac{DC}{6}=\frac{6}{9}[/tex]Let's solve for DC.
Multiply both sides by 6:
[tex]\begin{gathered} \frac{DC}{6}\ast6=\frac{6}{9}\ast6 \\ \\ DC=\frac{36}{9}=4 \\ \\ DC=4 \end{gathered}[/tex]ANSWER:
DC = 4