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What is the mass in grams of carbon dioxide that would be required toreact with 80.5 g of LiOH in the following chemical reaction?2 LiOH(s) + CO,(g) – LiCO,(s) + H2O(1)

Answer :

To solve this question we have to convert the given mass of litium hydroxide to moles using the molecular mass of this compound:

[tex]80.5g\cdot\frac{molLiOH}{23.95g}=3.36molLiOH[/tex]

Now, use the stoichiometric ratio given by the chemical equation:

[tex]3.36molLiOH\cdot\frac{1molCO_2}{2molLiOH}=1.68molCO_2[/tex]

Finally, convert the moles of CO₂ to g using the molecular mass of CO₂:

[tex]1.68molCO_2\cdot\frac{44g}{molCO_2}=73.92g[/tex]

The mass of carbon dioxide required to react with 80.5g of LiOH is 73.92g.

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