17.Find the missing side length to the near tenth.56°9XA. 11.3B10.6c. 6.1D. 13.3

13.3 (option D)
Explanation:angle = 56°
opposite = side opposite the angle = x
adjacent = base = 9
We would apply the trigonomretry ratio SOHCAHTOA
Since we know adjacent and we are looking for the opposite, we would use tan ratio (TOA)
tan 56° = opposite/adjacent
[tex]\begin{gathered} \tan 56\degree=\frac{x}{9} \\ x\text{ = 9(tan 56}\degree) \end{gathered}[/tex][tex]\begin{gathered} x\text{ = 9(}1.4826) \\ x\text{ = 13.3434} \end{gathered}[/tex]To the nearest tenth, the missing side length x is 13.3 (option D)