A bag of tokens contains 1010 red, 44 green, and 88 blue tokens. What is the probability that a randomly selected token is red and green? Enter your answer as a fraction

Answer :

Solution

Red = 10

Green= 4

Blue = 8

Total = 22

P ( red and green ) = P ( red ) X P(green )

P(red) = number of red balls / total number of balls

P(red) = 10/22

P(green) = 4/22

[tex]\begin{gathered} =\frac{10}{22}\times\frac{4}{22} \\ \\ =\frac{40}{484} \\ \\ =\frac{10}{121} \\ \end{gathered}[/tex]

NOTE : The use of 'AND ' in probability simply means multiplying the probabilities

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