There are 11 horses in a race. In how many ways can the first three positions of the order of the finish occur? (Assume there are no ties.)A. 990B. 163C. 165ООD. 994

There are 11 horses in a race. In how many ways can the first three positions of the order of the finish occur? (Assume there are no ties.)A. 990B. 163C. 165ООD class=

Answer :

Find the position of the order of the horse race:

Total number of horse = 11

The position of order are first , second and third = 3

[tex]^{11}C_{^{}3}[/tex][tex]\begin{gathered} ^{11}C_{^{}3}=\frac{11!}{(11-3)!3!} \\ ^{11}C_{^{}3}=\frac{11!}{8!3!}=\frac{11\text{ x 10 x 9 x 8!}}{8!\text{ 3 x 2 x }1} \\ \text{ }^{11}C_{^{}3}=\text{ 165} \end{gathered}[/tex]

Therefore the number of ways first three poisition will occur = 165

Hence the correct answer is Option C

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