There are 11 horses in a race. In how many ways can the first three positions of the order of the finish occur? (Assume there are no ties.)A. 990B. 163C. 165ООD. 994

Find the position of the order of the horse race:
Total number of horse = 11
The position of order are first , second and third = 3
[tex]^{11}C_{^{}3}[/tex][tex]\begin{gathered} ^{11}C_{^{}3}=\frac{11!}{(11-3)!3!} \\ ^{11}C_{^{}3}=\frac{11!}{8!3!}=\frac{11\text{ x 10 x 9 x 8!}}{8!\text{ 3 x 2 x }1} \\ \text{ }^{11}C_{^{}3}=\text{ 165} \end{gathered}[/tex]Therefore the number of ways first three poisition will occur = 165
Hence the correct answer is Option C