Answer :
Given:
The area of the rectangular loop is,
[tex]A=0.234\text{ m}^2[/tex]The current in the loop is,
[tex]I=0.622\text{ A}[/tex]The strength of the magnetic field is,
[tex]B=0.561\text{ T}[/tex]The angle of the loop with the magnetic field is,
[tex]\theta=51.029\degree[/tex]To find:
The magnitude of the torque on the loop
Explanation:
The torque on a current-carrying loop is,
[tex]\tau=IABsin\theta[/tex]Substituting the values we get,
[tex]\begin{gathered} \tau=0.622\times0.234\times0.561\times sin51.029\degree \\ =0.063\text{ A.m}^2.T \end{gathered}[/tex]Hence, the torque is,
[tex]\begin{equation*} 0.063\text{ A.m}^2.T \end{equation*}[/tex]