Answer :
Step 1
State the expression for the probability of an event to occur.
[tex]\text{The probability of an event =}\frac{number\text{ of required events}}{\text{Total number of events}}[/tex]Step 2
Find out the number of required events
Total number of events = 52 cards
[tex]\begin{gathered} A\text{ deck of cards has} \\ 4\text{ Suites - }hearts,\text{ clubs, spade and diamond.} \\ \text{and each suite has} \\ \mleft\lbrace ace,\text{ 2,3,4,5,6,7,8,9, jack, qu}een,\text{ king}\mright\rbrace \end{gathered}[/tex]Therefore, the number of aces = 4
The number of 6 = 4
Step 3
Find the probability of getting an ace or a 6.
[tex]\begin{gathered} \text{The probability of getting an ace =}\frac{number\text{ of aces in a deck of cards}}{\text{Total number of cards}} \\ \text{The probability of getting an ace}=\frac{4}{52} \\ \text{The probability of g}etting\text{ a 6 =}\frac{number\text{ of 6 in a deck of cards}}{\text{Total number of cards}} \\ \text{The probability of g}etting\text{ a 6}=\frac{4}{52} \end{gathered}[/tex]Therefore,
[tex]\text{The probability of drawing an ace or a 6 = }\frac{4}{52}+\frac{4}{52}=\frac{8}{52}=\frac{2}{13}[/tex]Hence, Option D