Answer :
Equation:
[tex]d^2\colon2c-b+3a[/tex]Replace d with 10, b with 9 , c with 5, and a with 1/3.
[tex]\frac{10^2}{2\cdot5}-9+3\cdot\frac{1}{3}[/tex]Solve:
[tex]\frac{100}{10}-9+1[/tex][tex]10-9+1[/tex][tex]2[/tex]
Equation:
[tex]d^2\colon2c-b+3a[/tex]Replace d with 10, b with 9 , c with 5, and a with 1/3.
[tex]\frac{10^2}{2\cdot5}-9+3\cdot\frac{1}{3}[/tex]Solve:
[tex]\frac{100}{10}-9+1[/tex][tex]10-9+1[/tex][tex]2[/tex]