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An object is taken to Mars. It’s mass is 15kg, it’s weight on Mars is 55.5N

What is the gravitational field strength on Mars?

Answer :

jacob193

Answer:

Approximately [tex]3.7\; {\rm N \cdot kg^{-1}}[/tex] (or equivalently, [tex]3.7\; {\rm m\cdot s^{-2}}[/tex].)

Explanation:

Gravitational field strength measures the force (weight) that the field exerts on object of unit mass (e.g., [tex]1\; {\rm kg}[/tex].)

Divide the weight of the object by its mass to find the gravitational field strength at the position.

In this question, [tex]\text{weight} = 55.5\; {\rm N}[/tex] while [tex]\text{mass} = 15\; {\rm kg}[/tex]. Therefore, the gravitational field strength will be:

[tex]\begin{aligned} & (\text{gravitational field strength}) \\ =\; & \frac{(\text{weight})}{(\text{mass})} \\ =\; & \frac{55.5\; {\rm N}}{15\; {\rm kg}} \\ =\; & 3.7\; {\rm N \cdot kg^{-1}} \end{aligned}[/tex].

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