Answer :
We will have the following:
[tex]A=\frac{45C}{0.58s}\Rightarrow Amp=\frac{2250}{29}Amp\Rightarrow A\approx77.59Amp[/tex]So there will be approximately 77.29 amperes passing through.
We will have the following:
[tex]A=\frac{45C}{0.58s}\Rightarrow Amp=\frac{2250}{29}Amp\Rightarrow A\approx77.59Amp[/tex]So there will be approximately 77.29 amperes passing through.