Answer :
Answer
453.9 kPa
Explanation
Given:
Initial volume, V₁ = 750.0 mL
Initial pressure, P₁ = 151.3 kPa
Final volume, V₂ = 250.0mL
What to find:
The new pressure when the volume is decreased to 250.0 mL.
Step-by-step solution:
The new pressure when the volume is decreased to 250.0 mL can be calculated using the Boyle's law formula below
[tex]\begin{gathered} P_1V_1=P_2V_2 \\ \\ \Rightarrow P_2=\frac{P_1V_1}{V_2} \end{gathered}[/tex]Plugging the values of the given parameters into the formula, we have
[tex]P_2=\frac{151.3kPa\times750.0mL}{250.0mL}=453.9kPa[/tex]The new pressure when the volume is decreased to 250.0 mL is 453.9 kPa
: