Answer :
Given data
*The given mass of the bookcase is m = 35 kg
*The given horizontal force is F = 150 N
*The coefficient of friction between the wooden floor and bookcase is
[tex]\mu=0.6[/tex]The formula for the magnitude of the static frictional force acting on the bookcase is given as
[tex]\begin{gathered} F_s=\mu N \\ =\mu mg \end{gathered}[/tex]*Here N = mg is the normal force
*Here g is the acceleration due to the gravity
Substitute the known values in the above expression as
[tex]\begin{gathered} F_s=(0.6)(35)(9.8) \\ =205.8\text{ N} \end{gathered}[/tex]Hence, the magnitude of the static frictional force acting on the bookcase is 205.8 N