Answer :
Problem
14) reflect across the line y = x
M(3,6) ► M'
N(5, 10) ► N
P(2,-5) →P
Solution
For this case we need to remember that if we have a point (x,y) when we reflect respect to the line y=x the new coordinates are (y,x)
And using this formula we have:
M' = (6,3)
N'= (10,5)
P' =(-5,2)