A rock group needs to choose 3 songs to play at the annual Battle of the Bands. How many ways can they choose their set if they have 15 songs to pick from?

Answer :

We need to find the number of combinations of 3 songs out of 15 songs.

The combination of r items out of a total of n items is given by the formula:

[tex]C(n,r)=\frac{n!}{r!(n-r)!}[/tex]

where

[tex]n!=n(n-1)(n-2)...(2)(1)[/tex]

In this problem, we have:

[tex]\begin{gathered} n=15 \\ r=3 \end{gathered}[/tex]

Thus, we obtain:

[tex]\begin{gathered} C(15,3)=\frac{15!}{3!(15-3)!} \\ \\ C(15,3)=\frac{15\cdot14\cdot13(12!)}{3\cdot2\cdot1(12!)} \\ \\ C(15,3)=\frac{15}{3}\cdot\frac{14}{2}\cdot13 \\ \\ C(15,3)=5\cdot7\cdot13 \\ \\ C(15,3)=455 \end{gathered}[/tex]

Answer: The number of ways they can choose their set of songs is 455.

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