Answer :
We can solve this system by elimination method.
If we multiply by -2 the second equation, we have
[tex]-2x-4y=-28[/tex]Then, we need to solve the following equivalent system:
[tex]\begin{gathered} 2x-6y=-12 \\ -2x-4y=-28 \end{gathered}[/tex]Now, we can see that if we add both equations, we obtain
[tex]-6y-4y=-12-28[/tex]because 2x-2x=0. Then, we have
[tex]\begin{gathered} -10y=-40 \\ y=\frac{-40}{-10} \\ y=4 \end{gathered}[/tex]Now, we can substitute this result into the first equation. It yields,
[tex]2x-6(4)=-12[/tex]which gives
[tex]\begin{gathered} 2x-24=-12 \\ 2x=-12+24 \\ 2x=12 \\ x=\frac{12}{2} \\ x=6 \end{gathered}[/tex]Therefore, the solution is x=6 and y=4.