Answer :
Let us revise the changes between units
[tex]1l=1dm^3=1000cm^3=1000ml[/tex]Now, let us find the missing in the table
a.
8 dm^3
By using the units above
[tex]\begin{gathered} 8dm^3=8\times1000=8000cm^3 \\ 8dm^3=8\times1=8l \\ 8dm^3=8\times1000=8000ml \end{gathered}[/tex]The missings in a are
8000 cm^3
8 l
8000 ml
b.
600 cm^3
By using the units above
[tex]\begin{gathered} 600cm^3=\frac{600}{1000}=0.6dm^3 \\ \\ 600cm^3=\frac{600}{1000}=0.6l \\ \\ 600cm^3=\frac{600}{1}=600ml \end{gathered}[/tex]The missings in the table are
0.6 dm^3
0.6 l
600 ml
c.
35 l
By using the units above
[tex]\begin{gathered} 35l=35\times1000=35000cm^3 \\ 35l=35\times1=35dm^3 \\ 35l=35\times1000=35000ml \end{gathered}[/tex]The missings in the table are
35000 cm^3
35 dm^3
35000 ml
d.
1000 ml
By using the units above
[tex]\begin{gathered} 1000ml=\frac{1000}{1}=1000cm^3 \\ \\ 1000ml=\frac{1000}{1000}=1dm^3 \\ \\ 1000ml=\frac{1000}{1000}=1l \end{gathered}[/tex]The missings in the table are
1000 cm^3
1 dm^3
1 l
e.
740 cm^3
By using the units above
[tex]\begin{gathered} 740cm^3=\frac{740}{1000}=0.74dm^3 \\ \\ 740cm^3=\frac{740}{1000}=0.74l \\ \\ 740cm^3=\frac{740}{1}=740ml \end{gathered}[/tex]The missings in the table are
0.74 dm^3
0.74 l
740 ml
f.
9200 cm^3
[tex]\begin{gathered} 9200cm^3=\frac{9200}{1000}=9.2dm^3 \\ \\ 9200cm^3=\frac{9200}{1000}=9.2l \\ \\ 9200cm^3=\frac{9200}{1}=9200ml \end{gathered}[/tex]The missings in the table are
9.2 dm^3
9.2 l
9200 ml