ME A Pound of Tea POW ID: 4087 Problem Print Jonathan and Hazel love to drink tea. When they are both at home a pound of lea lasis two weeks Occasionally Hazel visits her mother in Australia. It takes six weeks for Jonathan alone to use up a pound orlea How long should a pound of tea lasi Hazel if she were alone? Extra Extra in 2006 Hazel visited her mother for six weeks in the spring in the summer Jonathan gave up drinking tea for six weeks Their favonte tea costs $9.00 per pound About how much did the couple spend on tea during the year?

Answer :

Answer:

• 3 weeks

,

• $207

Explanation:

Part A

• Let the time it takes Hazel to finish 1 pound of tea = x weeks

,

• Jonathan alone uses up a pound of tea in six weeks.

,

• When they are both at home a pound of tea lasts two weeks.

This gives rise to the equation below:

[tex]\frac{1}{x}+\frac{1}{6}=\frac{1}{2}[/tex]

First, we solve for x:

[tex]\begin{gathered} \frac{1}{x}=\frac{1}{2}-\frac{1}{6} \\ \frac{1}{x}=\frac{3-1}{6} \\ \frac{1}{x}=\frac{2}{6} \\ 2x=6 \\ x=3\text{ weeks} \end{gathered}[/tex]

If Hazel were alone, a pound of tea would last 3 weeks.

Part B

There are a total of 52 weeks in a year.

• Hazel did not drink tea for 6 weeks

,

• Jonathan gave up drinking tea for six weeks.

The number of weeks for which they drank tea:

[tex]=52-6=46\; weeks[/tex]

1 pound of tea last 2 weeks.

Therefore, the number of pounds they drank:

[tex]\begin{gathered} =\frac{46}{2} \\ =23\text{ pounds} \end{gathered}[/tex]

Since the tea costs $9.00 per pound, the amount spent:

[tex]\begin{gathered} =23\times9 \\ =\$207 \end{gathered}[/tex]

The couple spends about $207 on tea during the year.

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