Answer :
Explanation:
The equations are given below as
[tex]\begin{gathered} 3x+4y=10----(1) \\ x-y=1------(2) \end{gathered}[/tex]From equation (2) make x the subject of the formula
[tex]\begin{gathered} x-y=1 \\ x=1+y-----(3) \end{gathered}[/tex]Substitute equation (3) in equation (1)
[tex]\begin{gathered} 3x+4y=10 \\ 3(1+y)+4y=10 \\ 3+3y+4y=10 \\ 3+7y=10 \\ collect\text{ similar terms, we will have} \\ 7y=10-3 \\ 7y=7 \\ \frac{7y}{7}=\frac{7}{7} \\ y=1 \end{gathered}[/tex]Substitute y=1 in equation (3)
[tex]\begin{gathered} x=1+y \\ x=1+1 \\ x=2 \end{gathered}[/tex]Hence,
Th solution of the system of equations is
[tex](x,y)\Rightarrow(2,1)[/tex]