Answer: The net ionic equation is written above and the products formed are strontium acetate and water molecule.
Explanation:
Neutralization reaction is defined as the reaction in which an acid reacts with a base to produce a salt and also releases water molecule.
Net ionic equation of any reaction does not include any spectator ions.
Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.
The chemical equation for the reaction of acetic acid and strontium hydroxide is given as:
[tex]2CH_3COOH(aq.)+Sr(OH)_2(aq.)\rightarrow Sr(CH_3COO)_2(aq.)+2H_2O(l)[/tex]
The products formed are strontium acetate and water molecule
Ionic form of the above equation follows:
[tex]2H^+(aq.)+2CH_3COO^-(aq.)+Sr^{2+}(aq.)+2OH^-(aq.)\rightarrow Sr^{2+}(aq.)+2CH_3COO^-(aq.)+2H_2O(l)[/tex]
As, strontium and acetate ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.
The net ionic equation for the above reaction follows:
[tex]2H^+(aq.)+2OH^-(aq.)\rightarrow 2H_2O(l)[/tex]
Hence, the net ionic equation is written above and the products formed are strontium acetate and water molecule.
