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Consider the neutralization reaction between CH3COOH and Sr(OH)2. Complete and balance the neutralization reaction, name the products, and write the net ionic equation.

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mpanderla95
I believe this would be the solution.
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sebassandin

Answer:

See the explanation.

Explanation:

Hello,

In this case, the overall double displacement undergoing chemical reaction turn out into:

[tex]Sr(OH)_2+2CH_3COOH-->(CH_3COO)_2Sr+2H_2O[/tex]

The names are:

[tex]Sr(OH)_2[/tex]: strontium hydroxide.

[tex]CH_3COOH[/tex]: acetic acid.

[tex](CH_3COO)_2Sr[/tex]: strontium acetate.

[tex]H_2O[/tex]: water.

Now, the net ionic equation is obtained from the following procedure:

[tex]Sr^{+2}(aq)+OH^-(aq)+CH_3COOH(aq)-->CH_3COO^-(aq)+H_2O(l)+Sr^{+2}\\OH^-(aq)+CH_3COOH(aq)-->CH_3COO^-(aq)+H_2O(l)[/tex]

In which it is seen that the strontium ion is cancelled as it is completely dissociated unlike the acetate at the left side.

Best regards.

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