Answer :
The first is an ordered list of integers, the second is an ordered list of integers, and the third is an unsorted list of texts in JAVA. (Refer to the coding shown below.)
What is JAVA?
In order to have as few implementation dependencies as feasible, Java is a high-level, class-based, object-oriented programming language.
Java is an object-oriented, cross-platform programming language (OOP).
JavaScript, a scripting language used to build dynamic web pages, should not be confused with it.
Java is one of the most widely used programming languages in the world because of its dependability and simplicity.
So, the generic class needed to compare any kind of data structure is created by the Java code that follows.
Both integers and strings were employed in three different test situations.
The first is a list of integers in ascending order, the second is a list of integers in descending order, and the third is a list of texts that are not sorted.
The image below that is attached shows the results.
import java.util.Scanner;
class Brainly {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.println("Order: " + checkOrder(10, 22, 51, 53));
System.out.println("Order: " + checkOrder(55, 44, 33, 22));
System.out.println("Order: " + checkOrder("John", " Gabriel", "Daniela", "Zendaya"));
}
public static <E extends Comparable<E>> int checkOrder(E var1, E var2, E var3, E var4) {
E prevVar = var1;
if (var2.compareTo(prevVar) > 0) {
prevVar = var2;
} else {
if (var3.compareTo(prevVar) < 0) {
prevVar = var3;
} else {
return 0;
}
if (var4.compareTo(prevVar) < 0) {
return 1;
} else {
return 0;
}
}
if (var3.compareTo(prevVar) > 0) {
prevVar = var3;
}
if (var4.compareTo(prevVar) > 0) {
return -1;
}
return 0;
}
}
Therefore, the first is an ordered list of integers, the second is an ordered list of integers, and the third is an unsorted list of texts in JAVA. (Refer to the coding shown below.)
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