Answer :
The gauge pressure at the oil-water interface and at the bottom of the barrel is 705.6 Pa and 3155.6 Pa.
The barrel contains 0.10m of oil and floating on water that is 0.250mm deep.
The density of the oil is given to be 600 kg/m³.
a) The gauge pressure at the oil water interface is given by,
P = pgh
Where,
p is density of oil and h is the hieght of the oil,
Putting values,
P = 0.120 x 600 x 9.8
P = 705.6 Pa.
So, thr pressure at oil-water interface is 705.6 Pa.
(b) The pressure at the bottom of the barrel can be found as,
P = pgh + pxH
Where,
H is the height of the water and x is the density of water,
Assigning value,
P = 705.6 + 1000 x 9.8 x 0.250
P = 705.6 + 2450
P = 3155.6 Pa.
So, the pressure at the bottom of the barrel is 3155.6 Pa.
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