Answer :
Differentiation reverses the parity of a function, means if f(x), is an even function, then its derivative f'( x ) is odd which is true i.e f(x) is even function implies f'(x) is odd and if f(x) is odd function implies f'(x) is even .
First, let's we start with the definition of even and odd functions.
f is even if and only if f(x) = f(-x) --(1)
f is odd iff f(x) = -f(-x) ---(2)
If f is even and differentiating equation (1) we get,
f'(x) = f'(-x)× (-1) = -f'(-x).
f'(x) = - f'(-x).
Since, f'(x) is some function, then let
g(x) = f'(x) So, we see g(x) = -g(-x) which shows that the derivative of an even function is an odd function.
If f is odd then: f(x) = -f(-x)
differentiating above function with respect to x we get ,
f'(x) = -f'(-x)× (-1 ) = f'(-x).
Let g(x) = f'(x), then g(x) = g(-x) which shows that the derivative of an odd function is an even function.
Hence, Differentiation reverses the parity is hold.
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