Is the distance from the merry-go-round to the water slide the same as the distance from the water slide to the merry-go-round? Explain.

Is the distance from the merry-go-round to the water slide the same as the distance from the water slide to the merry-go-round? Explain. class=

Answer :

Answer:

Yes, it’s the same.

Step-by-step explanation:

Merry-go-around: (8, 2)

Water Slide: (8, -8)

Since the x-axis are the same, we can cross them out.

Different Quadrant: Add

|2| + | -8 | = 10 miles/10 squares

If you do the reverse, it’s the same. Unless if you stop somewhere between, their distance are the same.

Yes, the distance from the merry-go-round to the water slide is the same as the distance from the water slide to the merry-go-round.

Given:

Coordinates of different rides in a park on the graph.

To find:

to find whether the distance from the merry-go-round to the water slide is the same as the distance from the water slide to the merry-go-round.

Solution:

The coordinates of merry-go-round = M = (8,2)

The coordinates of water slide = W = (8,-8)

The distance between the merry-go-round to the water slide.

Using distance formula,  [tex](x_1,y_1);(x_2,y_2)[/tex]::

[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

[tex]MW = \sqrt{(8-8)^2+(-8-2)^2}\\\\=\sqrt{(-10)^2}\\\\MW=10 units[/tex]

The coordinates of water slide = W = (8,-8)

The coordinates of merry-go-round = M = (8,2)

The distance between the water slide to the merry-go-round:

Using distance formula, [tex](x_1,y_1);(x_2,y_2)[/tex]:

[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

[tex]WM = \sqrt{(8-8)^2+(2-(-8))^2}\\\\=\sqrt{(10)^2}\\\\MW=10 units[/tex]

MW = WM = 10 units

Yes, the distance from the merry-go-round to the water slide is the same as the distance from the water slide to the merry-go-round.

Learn more about the distance formula here:

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