Answer :
First you have to set up the equation which would be 20+1x=30+.50x
You can't have a c variable on both sides so I have to subtract .50x on both sides
20+1x=30+.50x
-.50x. -.50x
-----------------------
20+.50x=30
Now you have to subtract 20 from both sides
20+.50x=30
-20 -20
-------------------
.50x=10
Once you get to this point you divide both the .50x and 10 by .50
.50x=10
.50x/.50=10/.50
-----------------------
X=20
The final answer would be that it takes 20 deliveries for the amount of money to be the same for both pay schedules.
(If you want to check the answer you can plug 20 in for x with out starting equation)
You can't have a c variable on both sides so I have to subtract .50x on both sides
20+1x=30+.50x
-.50x. -.50x
-----------------------
20+.50x=30
Now you have to subtract 20 from both sides
20+.50x=30
-20 -20
-------------------
.50x=10
Once you get to this point you divide both the .50x and 10 by .50
.50x=10
.50x/.50=10/.50
-----------------------
X=20
The final answer would be that it takes 20 deliveries for the amount of money to be the same for both pay schedules.
(If you want to check the answer you can plug 20 in for x with out starting equation)