Answered

calculate the mass defect of the nitrogen nucleus 14 7n 714n . the mass mnmn of neutral 14 7n 714n is equal to 14.003074 atomic mass units.

Answer :

Mass defect is defined by the difference in the isotopic mass and the atomic mass. The mass defect in the nucleus of the nitrogen atom is 0.11235 amu.

What is a mass defect?

The mass defect has been the difference between the actual and the predicted atomic mass of the elemental atom. The predicted mass is calculated by simply adding the number of neutrons and the proton present inside the nucleus. The actual mass of the atom has been seen to be less than the predicted atomic mass of the atom.

Mass of neutral nitrogen atom = 14.003074 amu

It is already known that,

Mass of protons = 1.00728 amu

Mass of neutrons = 1.0086 amu

Mass of electron = 0.000549 amu

The given element ¹⁴N₇ contains seven electrons, protons, and neutrons in its structure. The mass defect is calculated as:

= (7 × 1.00728) - (7 × 1.0086) - (7 × 0.000549) - 14.003074

= 0.11235 amu

Therefore, the mass defect in nitrogen is 0.11235 amu.

Learn more about the Mass defects from given link

brainly.com/question/11624098

#SPJ4

Other Questions