Problems 2-3 refer to the following situation. A lake has a depth of
27.5 m
. The lake is filled with water, with has a density of
1000 kg/m^3
. Since the top of the lake is open to the air, the pressure at the top of the lake is the atmospheric pressure,
P 0â€‹ =1.0Ã—10^5
. Problem 2: What is the pressure at the bottom of the lake? a.
1.7Ã—10^5 Pa
b.
3.7Ã—10^5 Pa
c.
5.7Ã—10^5 Pa
d.
7.7Ã—10^5 Pa
Problem 3: An underwater vehicle is at the bottom of the lake. The vehicle has a circular window of radius
0.175 m
. What is the force on this window, due to the water? a.
1.6Ã—10^4 N
b.
3.6Ã—10^4 N
c.
5.6Ã—10^4 N
d.
7.6Ã—10^4 N

To find the pressure at the bottom of the lake, you can use the formula for hydrostatic pressure: P = P0 + rho * g * h Where P is the pressure at the bottom of the lake, P0 is the atmospheric pressure at the top of the lake, rho is the density of the water, g is the acceleration due to gravity, and h is the depth of the lake. Plugging in the given values, you get: P = 1.0 x 10^5 Pa + 1000 kg/m^3 * 9.8 m/s^2 * 27.5 m This gives a pressure at the bottom of the lake of: P = 3.7 x 10^5 Pa. To find the force on the circular window, you can use the formula for the force exerted by a fluid on a surface: F = P * A Where F is the force on the window, P is the pressure at the bottom of the lake, and A is the area of the window. The area of the window can be calculated using the formula for the area of a circle: A = pi * r^2 Where A is the area of the window, pi is the mathematical constant pi (approximately 3.14), and r is the radius of the window. Plugging in the values, you get: F = 3.7 x 10^5 Pa * (pi * (0.175 m)^2) This gives a force on the window of: F = 3.6 x 10^4 N So the answer to problem 3 is b. 3.6 x 10^4 N.

To know more about pressure-

https://brainly.com/question/29341536

#SPJ4