the distance that a free falling object falls is directly proportional to the square of the time it falls (before it hits the ground). if an object fell 83ft in 3 seconds, how far will it have fallen by the end of 6 seconds? round your answer to the nearest integer if necessary.

Answer :

The distance the object will have fallen after 6 sedconds is 332ft

What is variation?

A variation is a relation between a set of values of one variable and a set of values of other variables.

Direct variation

In the equation y = mx + b, if m is a nonzero constant and b = 0, then you have the function y = mx (often written y = kx), which is called a direct variation. That is, you can say that y varies directly as x or y is directly proportional to x. In this function, m (or k) is called the constant of proportionality or the constant of variation. The graph of every direct variation passes through the origin.

le the distance be d and he time be t

so that d ∝[tex]t^{2}[/tex]

removing the proportionality sign and replacing it with a constant k

d = kt^2

when d = 83, t = 3

83 = k(3)^2

83 = 9k

k = 83/9

the equation becomes

d = 83/9 (t)^2

when t = 6, d becomes

d = 83/9 x(6)^2

d = 83/9 x 36

d = 332ft

In conclusion d = 332ft

Learn more about direct variation: https://brainly.com/question/6499629

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