Answer :

Banabanana
If two chords intersect inside a circle, then the measure of the angle formed is one half the sum of the measure of the arcs intercepted by the angle and its vertical angle.

[tex] \frac{arc \ SR+arc \ TU}{2}=63 \\ \\ 55+arc \ TU=63*2 \\ \\55+arc \ TU=126\\\\ \ arc \ TU = 126-55=71^o[/tex]
calculista

Answer:

[tex]arc\ TU=71\°[/tex]

Step-by-step explanation:

we know that

The measure of the interior angle is the semi-sum of the arcs comprising it and its opposite

In this problem we have that

[tex]63\° =\frac{1}{2}(arc\ SR+arc\ TU)[/tex]

we have

[tex]arc\ SR=55\°[/tex]

substitute and solve for arc TU

[tex]63\° =\frac{1}{2}(55\°+arc\ TU)[/tex]

[tex]126\° =(55\°+arc\ TU)[/tex]

[tex]arc\ TU=126\°-55\°=71\°[/tex]

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