Four circles, each with a radius of 2 inches, are removed from a square. What is the remaining area of the square? (16 – 4π) in.2 (16 – π) in.2 (64 – 16π) in.2 (64 – 4π) in.2Four circles, each with a radius of 2 inches, are removed from a square. What is the remaining area of the square? (16 – 4π) in.2 (16 – π) in.2 (64 – 16π) in.2 (64 – 4π) in.2vvvv

Answer :

Answer: [tex]64-16\pi[/tex] unit square.

Step-by-step explanation:

Here, four circle are removing from a square from the square of edge 8.

Since, The area of the square= [tex]8^2=64[/tex] square unit  ( because, area of square=side×side)

The area of a circle with radius 2 = [tex]\pi(2)^2=4\pi[/tex] square unit.

The area of four circle of radius 2= [tex]4\times4\pi=16\pi[/tex] square unit.

According to the question, these four circle are removed by the above square.

Therefore remaining area of the square after removing these four circle=area of the square- area of four circle of radius 2= [tex]64-16\pi[/tex] square unit.


The remaining area of the square is 64 - 16π.

What is a circle?

A circle is a bounded figure in which points from its center to its circumference is equidistant.

Area of a circle = πr²

Where :

π = pi = 22/7

R = radius

Area of one circle = 2²π = 4π

Area of four circles = 4 x 4π = 16π

What is a square?

A square is a quadrilateral with four equal sides.

Characteristics of a square includes:

Area of a square = length²

= (2x4)²

= 64

The remaining area of the square = 64 - 16π

To learn more about the area of a circle, please check: https://brainly.com/question/14351152

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