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A department store is holding a drawing to give away free shopping sprees. There are 10 customers who have entered the drawing: 2 live in the town of Gaston, 3 live in Pike, and 5 live in Wells. Two winners will be selected at random. What is the probability that the first winner lives in Pike and the second lives in Wells? Write your answer as a fraction in simplest form.

Answer :

operrt
The way to find probability is to add all of them together so 10
There are 3 in Pike so the probability is 3/10 Now you remove them I assume. If so then the answer is if the second lives in Wells the answer would be 5/9 if the winner is not removed which I assume is not the case then it would be 5/10 or 1/2

Answer:

[tex]\frac{3}{10}[/tex] and [tex]\frac{5}{9}[/tex]

Step-by-step explanation:

Total number of customers entering the drawing = [tex]10[/tex]

Number of customers from Gaston = [tex]2[/tex]

Number of customers from Pike = [tex]3[/tex]

Number of customers from Wells = [tex]5[/tex]

Now the probability for the first winner to be from Pike will be

[tex]\frac{Number of customers from Pike}{Total customers} = \frac{3}{10}[/tex]

Now, as the first winner is declared, total customer remaining will be [tex]9[/tex]

∴ Probabikity of second winner to be from Wells will be-

[tex]\frac{Number of customers from Wells}{Remaining customers} = \frac{5}{9}[/tex]

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