Answer :
2⁽ˣ⁺¹⁾ = 3ˣ
ln[2⁽ˣ⁺¹⁾] = ln(3ˣ)
(x+1).ln(2) = x.ln(3)
Expand:
x.ln(2) + ln(2) = x.ln(3)
x.ln(2) - x.ln(3) = - ln(2)
x[ln(2) - ln(3)] = - ln(2)
x = [ - ln(2)] / [ln2) - ln(3)
And x = 1.7095
ln[2⁽ˣ⁺¹⁾] = ln(3ˣ)
(x+1).ln(2) = x.ln(3)
Expand:
x.ln(2) + ln(2) = x.ln(3)
x.ln(2) - x.ln(3) = - ln(2)
x[ln(2) - ln(3)] = - ln(2)
x = [ - ln(2)] / [ln2) - ln(3)
And x = 1.7095