Answer:
The third vertex of triangle is (2a,0)
Step-by-step explanation:
We are given the following information in the question:
A right angled triangle such the longer side is twice the length of the shorter side.
We have to find the coordinate of the third vertex of triangle.
Let A(0,a), B(0,0), C(x,0)
Distance between two points with coordinate [tex](x_1,y_1), (x_2,y_2)[/tex] is given by:
[tex]\sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}[/tex]
Now, we are given that the longer side is twice the length of the shorter side.
Thus, we can write:
[tex]AC = 2AB\\\sqrt{(x-0)^2 + (0-0)^2}= 2\sqrt{(0-0)^2 + (a-0)^2}\\\pm x = \pm 2a\\\text{Since the point lies on the positive side of x-axis}\\x = 2a[/tex]
The third vertex of triangle is (2a,0)