What is the area of triangle ABC? Round to the nearest tenth of a square unit.

Answer:
[tex]=61.8 units^2[/tex].
Step-by-step explanation:
In the picture we have that a = 13, b= 10 and C = 72°. Then,
[tex]Area = \frac{1}{2}absin(C)[/tex]
[tex]= \frac{1}{2}(13)(10)sin(72\°)[/tex]
[tex]= 65sin(72\°)[/tex]
[tex]=61.8 units^2[/tex].