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Today at 6:38 AM
Chemistry

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What is the approximate energy of a photon having a frequency of 4 × 107 hz? ( h = 6.6 × 10-34 j.s)?

Answer :

Today at 6:43 AM

E = h*f
E= 6.6x10^-34x 4x10^7
= (6.6x4)x10^-27
=26.4x10^-27
E=2.64X10^-26 J

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