Answer :
I don't know what 10p is so before I answer I'd have to know what that is
The problem conditions give rise to 2 equations in 3 unknowns. Let L, M, N represent the number of Luxury, Mini, and Normal packets sold.
.. L +M +N = 100 . . . . . . the number of packets sold
.. 5L +0.1M +N = 100 . . the value of donations
These result in the relationships
.. L = (9/40)M
.. N = 100 -(49/40)M
There are three integer solutions in which the numbers are non-negative.
.. (L, M, N) = (0, 0, 100) or (9, 40, 51) or (18, 80, 2)
If Marianne sold 100 normal packets, her stock would be "very low" compared to the others.
If Marianne sold 51 normal packets, her stock may be "very low" with respect to the others, depending on how many of each she started with. This might be the solution if we require non-zero numbers of all packets were sold.
.. L +M +N = 100 . . . . . . the number of packets sold
.. 5L +0.1M +N = 100 . . the value of donations
These result in the relationships
.. L = (9/40)M
.. N = 100 -(49/40)M
There are three integer solutions in which the numbers are non-negative.
.. (L, M, N) = (0, 0, 100) or (9, 40, 51) or (18, 80, 2)
If Marianne sold 100 normal packets, her stock would be "very low" compared to the others.
If Marianne sold 51 normal packets, her stock may be "very low" with respect to the others, depending on how many of each she started with. This might be the solution if we require non-zero numbers of all packets were sold.