thetrojantv thetrojantv

Today at 7:35 PM
Mathematics

Answered

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Answer :

creeds25 creeds25

Today at 7:41 PM

[tex] \sqrt{-80} \\ [/tex]
We can write it as:
[tex] \sqrt{-1} \times \sqrt{80} [/tex]
Apply imaginary number rule:
[tex] \sqrt{-1} =i[/tex]
We get
[tex] =\sqrt{80} i[/tex]
Now factorise 80.
80=4 x 4 x 5 = 4² x 5
[tex] \sqrt{80}i = \sqrt{4^2 \times 5} i [/tex]
[tex] =\sqrt{4^2} \times \sqrt{5} i \\ =4 \sqrt{5} i[/tex]
[tex]Answer: \ 4 \sqrt{5} i[/tex]

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carlosego carlosego

Today at 7:41 PM

For this case what you should do is rewrite the function.
We then have to rewrite:
root (-80)
root (- (16 * 5))
4raiz (-5)
Then remember that:
Root (-1) = i
We have then:
4raiz (5) i
Answer:
The equivalent expression is:
4raiz (5) i
(option 3)

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