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Two charged parallel plates are 0.25 meters away from each other. The field between the plates is 600 . What is the electric potential difference?

Answer :

skyluke89
I assume that "600" is [tex]600 V/m[/tex].

The relationship between the intensity of the electric field E and the potential difference [tex]\Delta V[/tex] is given by
[tex]\Delta V = Ed[/tex]
where d is the distance between the two points at which the potential difference is calculated.
Using [tex]E=600 V/m[/tex] and [tex]d=0.25 m[/tex], we find
[tex]\Delta V=Ed=(600 V/m)(0.25 m)=150 V[/tex]
kerena8291

Answer:

ΔV = 150 V

Explanation:

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