The sum of two numbers is 400. If the first number is decreased by 20% and the second number is decreased by 15%, then the sum would be 68 less. Find the numbers after the decrease.

Answer :

backseatdog
Let x = the first number
Let y = the second number

So we can set up two equations:
x+y = 400
.8x + .85y = 400-68

Use substitution:
y = 400 - x
.8x + (.85)*(400-x) = 332
.8x + 340 -.85x = 332
8 = .05x
x = 160

So that makes y = 240

We want the decreased values so:

160*.8 = 128
240*.85 = 204

So the answers are 128 and 204

The numbers after decreasing are 128 and 204.

What is Equation?

An equation is a mathematical statement with an '=' symbol between two expressions that have equal values.

Here, Let,  x = the first number

and y = the second number

So our equations:

x + y = 400

0.8x + 0.85y = 400-68 = 332

Use substitution method:

y = 400 - x

0.8x + (0.85) X (400-x) = 332

0.8x + 340 - 0.85x = 332

8 = 0.05x

x = 160

Now, put the value of x in first equation, we get

y = 240

We want the decreased values so:

160 X 0.8 = 128

240 X 0.85 = 204

Thus, the numbers after decreasing are 128 and 204.

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